Main Page/PHYS 4210/Coaxial Cable

Coaxial Cable

You should carefully read Experiment 1 in The Art of Experimental Physics, Preston and Dietz. This write-up is meant to supplement that material.

Theory

A coaxial cable (coax) is one of the most popular means for transmitting the electromagnetic power from a generator to a receiver. It consists of an inner and outer conducting lines (usually made of copper) separated by a dielectric layer (usually teflon). The electromagnetic wave can propagate in a coax in the form of TE, TM, and TEM modes, and the latter is the one that is most commonly used. In this experiment, the effect of a coaxial cable on the propagating signal and some physical characteristics of a coax are studied.

There are two levels of description of electromagnetic phenomena. The more fundamental one relies on Maxwell’s equations combined with material equations. Within this approach, one uses the language of electric and magnetic field strengths, potentials, dielectric susceptibility and magnetic permeability, etc. Engineers, however, prefer a simpler language of currents, voltages and lump elements, that is, resistance, capacitance, conductance, and inductance. In order for this simplified description to be applicable to the problem considered, the characteristic sizes of lump elements must be much smaller than the wavelength of an electromagnetic wave. Nevertheless, with a small modification, the approach of engineers allows us to obtain some meaningful results even when this requirement is not met. We will adopt the language of engineers in the following discussion.

The idea of the modification is that, instead of using the net inductance, capacitance, resistance and conductance, we use their values per unit length. Thus, a coax is viewed as a system with distributed parameters. Let us write down the expressions for the unit-length characteristics of a coax. A current in the central conductor sets up a magnetic field; hence, the line has inductance whose value per unit length is

(1)

where μ is magnetic permeability of the dielectric layer between the two conductors, and a and b are the radii of the inner and outer conductors, respectively.

Next, the capacitance per unit length between the two conductors is:

(2)

where ε is the dielectric permittivity of the dielectric layer.

Since both inner and outer conductors are not ideal, the line has a resistance per unit length

(3)

Here, μ_c and σ_c are the magnetic permeability and conductivity of the conductors, respectively. The resistance value (3) is determined by the skin depth that measures the characteristic distance of penetration of the electromagnetic wave into the conductors. It is within the skin layer that the absorption of the electromagnetic power is most intense. The skin depth, in turn, depends on the frequency, ν, of the wave, hence R depends on ν as well.

Finally, the dielectric separating the two conductors is not ideal, hence there always is a leakage current when the conductors are kept at different potentials. This effect is accounted for by introducing the conductance per unit length of the line

(4)

σ being the conductivity of the dielectric layer.

ExerciseDerive (1) and (2). Hint: to derive (1), suppose that some current J flows through the inner conductor of the line. Find the value of the magnetic field produced by this current, and then the magnetic field energy stored in a unit length element of the line. This energy also equals LJ²/2, from the definition of inductance per unit length. To derive (2), assume that the inner and outer conductors have charges per unit length equal to +q and –q. Find the potential difference between the two conductors. From the definition of a unit length capacitance, the potential difference equals to qC.

A coax can be thought of as a collection of infinitely many infinitesimal elements, each of which can be presented with an equivalent circuit shown in Fig. 1 (similar to Fig. 1.4 of Preston).

Figure 1 - Coaxial cable cross sectional view.

As the current travels along the inner conductor, its total decrease on the element Δz is the sum of the leakage currents through the capacitance and displacement current. The former equals to GΔzV , and the latter to CΔz(dV/dt). Considering the node that joins the inductance, conductance, and capacitance, the first Kirchoff’s law yields:

(5)

Rearranging the terms and taking the limit Δz → 0 , we obtain

(6)

Similarly, a voltage drop on this element equals the electromotive force of self-induction and the voltage developed across the resistance:

(7)

ExerciseDerive (7). Use the second Kirchoff’s law to find the voltage drop across Δz.

Differentiating the last two equations with respect to z, we obtain:

(8)

(9)

ExerciseShow this.